Solving Diffraction Grating Homework Problem

AI Thread Summary
The homework problem involves calculating the number of lines in a diffraction grating using a monochromatic light wavelength of 600 nm. The setup includes observing two lamps positioned 0.30 m from the central light source, viewed from a distance of 2 m. The relevant equation is sinθ = (n*λ)/d, where d represents the distance between grating lines. The attempt at a solution suggests using sinθ as approximately 0.15 (0.3 m/2 m) for the first-order diffraction (n=1) to find d, but the width of the grating is not provided, complicating the calculation of the total number of lines. The discussion highlights the ambiguity in the problem statement.
ZxcvbnM2000
Messages
62
Reaction score
1

Homework Statement



When a monochromatic light of wavelength 600 nm is viewed 2 m away through a diffraction grating, two similar lamps are observed, one on each side of it, and each 0.30 m away from it. Calculate the number of lines in the grating

Homework Equations



sinθ = (n*λ)/d


The Attempt at a Solution



I don't even know how to sketch the diagram !

From what i understand d=0.3 m but we don't know n !
 
Physics news on Phys.org
If the image is formed 2m away at a distance of 0.3m from the 'straight through' position I would take Sinθ to be approx 0.3/2
Use this in the equation with n=1 (1st order) to find 'd'
This gives you the separation of lines in the grating. To calculate the number of lines in the grating you need to know how wide it is and... this is not given.
Vague question
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top