Diode OR Gate - the role of resistor

AI Thread Summary
Removing the resistor from a diode OR gate while maintaining the ground connection results in an undefined output voltage when both inputs are low. The resistor ensures that the output remains low when inputs are at zero potential, defining the output state. In digital logic, a low output is typically considered to be in the range of 0 - 2V, with specific thresholds varying by technology, such as 0V-0.8V for TTL devices. The output is grounded through the resistor, which creates a voltage drop rather than a direct connection to ground. When calculating current, the output branch and the resistor-ground branch should be treated as parallel connections, although the voltage remains the same across both.
dobry_den
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Hi! What would happen if the resistor in the attached diode OR gate removed (connection with the ground would be preserved)?
 

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It ensures that the output is low when both of the inputs are low. Without the resistor, the output voltage would be undefined in that case.
 
What do you mean by the word "low".. like when the inputs are of zero potential, when they're grounded? In that case the output would be also grounded and therefore defined... Or am I mistaken?
 
In digital logic, a logic zero or low would occur when the input is somewhere in the range of 0 - 2V. Its probably less than 2V, that varies depending on technology being used. For TTL devices, I believe it 0V-0.8V for a logic zero.

The output is always grounded via the resistor i.e. the output is voltage drop across the resistor and not taken directly from ground.
 
ok, thanks a lot. Another problem occurs when I am about to calculate the current in the output - should I take the output branch and the resistor-ground branch as connected in parallel?
 
Yup. The current through the resistor is not the same current going to the load connected to the output. The voltage however is the same.
 
Ok, that makes it clear. Thanks
 
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