Diode paralell with a resistor problem.

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Homework Help Overview

The discussion revolves around a circuit involving a diode and a resistor in parallel, where the behavior of current readings on an ammeter is analyzed when the polarity of the power supply is switched. Participants explore the implications of diode biasing and resistance in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the effective resistance of a diode in different bias states and how this affects current readings. Questions arise about the implications of switching the power supply and the unknown contents of the matchbox.

Discussion Status

There is an ongoing exploration of the relationship between diode behavior and current readings. Some participants provide insights into resistance calculations and the nature of forward and reverse bias, while others express uncertainty about the concepts involved.

Contextual Notes

Participants note that the exact contents of the matchbox were initially unknown, and assumptions about the diode's behavior under different conditions are being questioned. The discussion is framed within the constraints of a homework assignment, with some participants acknowledging gaps in their understanding of the material.

lionely
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Today my teacher asked us a question

2jdh01j.png



Basically he said a match box was taped shut and a current was passed through the circuit a reading came up on the Ammeter, then the cell was switched around, and a current ran through the circuit but the Ammeter read a smaller reading than before. Why?
 
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lionely said:
Today my teacher asked us a question

2jdh01j.png



Basically he said a match box was taped shut and a current was passed through the circuit a reading came up on the Ammeter, then the cell was switched around, and a current ran through the circuit but the Ammeter read a smaller reading than before. Why?

A lower current would indicate a higher resistance. What do you know about the effective resistance of a diode in forward bias and reverse bias.
 
Reverse bias resistance higher umm the thing is I know all of that stuff. But I forgot to say My teacher said we don't know what's in the box... after sometime of guessing he told us that it was a diode and resistor in parallel.
 
lionely said:
Reverse bias resistance higher umm the thing is I know all of that stuff. But I forgot to say My teacher said we don't know what's in the box... after sometime of guessing he told us that it was a diode and resistor in parallel.

Lets suppose that a diode has a resistance of 1Ω in forward bias, and 100Ω in reverse bias [you can investigate more reasonable figures - I just made them up]

If the diode was in parallel with a 100Ω resistor you can calculate the effective resistance.

When both are 100Ω we get 50Ω
When 1 is 100Ω and the other only 1Ω we know the effective resistance is < 1Ω
[when resistors are in parallel, the effective resistance is always less than the smallest resistor involved]

< 1Ω would allow a much higher current that 50Ω.
 
Oh, I understand. But I'm not really sure how a diode works, in the question it said only the cell was altered and not like the position of the match box so the diode inside would always be forward bias?
 
lionely said:
Oh, I understand. But I'm not really sure how a diode works, in the question it said only the cell was altered and not like the position of the match box so the diode inside would always be forward bias?

Forward and reverse bias refers to "which end" is connected to which terminal of the power supply.

If you swap the battery round, you alter the bias!
 
OH! Sorry I didn't know I didn't do my homework on this part of electricity so I don't know it well :( Sorry. I need to do it but thank you so much this made it so much clearer!
 

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