Directed Line Segment Joining (1,1,1) to (1,3,1)

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To find the directed line segment from (1,1,1) to (1,3,1), the correct representation is (1,1,1) + (0,2,0)t, where t must be constrained to define a segment rather than a full line. The parameter t should range from 0 to 1 to specify the segment, ensuring it starts at (1,1,1) and ends at (1,3,1). The discussion emphasizes the importance of defining direction, as the problem does not specify whether the direction is from (1,1,1) to (1,3,1) or vice versa. Clarifying the direction is crucial for accurately representing the directed line segment. Understanding the distinction between a line segment and a line is essential for solving this problem correctly.
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Homework Statement



Find the directed line segment joining (1,1,1) to (1,3,1)

Homework Equations





The Attempt at a Solution



(1,1,1) + (0,2,0)t is that correct?
 
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cse63146 said:
(1,1,1) + (0,2,0)t is that correct?
Is it a directed line segment?
Does it start at (1,1,1)?
Does it end at (1,3,1)?

If so, then it's correct.
 
Notice the "start and stop". You will need conditions on t as well as, for the "directed" part, something like "as t goes from ___ to ___".
 
you mean like this:

for all t \rightarrow \Re

or what I am trying to say is that for all t that are real numbers (couldn't find the symbol for it; looks like a small 'e')
 
No, the whole point is that t cannot be "all real numbers". That could give the entire line, not the line segment. And you still haven't dealt with the "directed" part. Do you understand the difference between a line segment and a line? Do you understand what a directed line or directed line segment is?
 
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0 \leq t \leq 1
 
Okay, that gives the "segment". Now what about the "directed" part? Unfortunately, your original statement of the problem doesn't give a direction. You just said "the directed line segment joining (1,1,1) to (1,3,1)" which does not state a direction. Is the direction from (1, 1, 1) to (1, 2, 1) or from (1, 2, 1) to (1, 1, 1)?
 
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