Directional Derivative of a Function in a Given Direction

gtfitzpatrick
Messages
372
Reaction score
0

Homework Statement



Find the Directional derivative of \varphi = x2+siny-xz in the direction of i+2j-2k at the point (1, \pi/2 , -3)

The Attempt at a Solution



u = i+2j-2k

\left|u\left| = \sqrt{1^2+2^2+(-2)^2} = 3


\Rightarrow u\hat{} = 1/3i+2/3j-2/3k

\nabla\varphi = (2x-z)i+(Cos y)j-xk

at the point (1, \pi/2 , -3)
u\hat{}\nabla\varphi = 5/3 + 0 +2/3 = 7/3

i think i have this right?
 
Physics news on Phys.org
I think you have it right.
 
thanks a mill
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top