Discrete Math: Finding Angle Between Plane & XZ Axis

AI Thread Summary
To find the angle between a plane and the xz-axis, one must consider the normals of the planes. The angle between two planes is determined by the angle between their normal vectors. For a plane represented by Ax + By + Cz = D, the normal vector is Ai + Bj + Ck, while the xz-plane has a normal vector of j. The cosine of the angle θ between the planes can be calculated using the formula cos(θ) = B / √(A² + B² + C²). This approach provides a clear method for determining the angle between the specified plane and the xz-axis.
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How do you find the angle between the co-ordinate axis (i.e. the xz plane) and another plane in general?
 
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eme_girl said:
How do you find the angle between the co-ordinate axis (i.e. the xz plane) and another plane in general?

Angle between two planes is the angle between the normals of the planes.
 
Expanding on what learningphysics said, if one plane is given by Ax+ By+ Cz= D and the other by ax+ by+cz= d, then the normal vectors are Ai+ Bj+ Ck and ai+ bj+ ck respectively. u.v= |u||v|cos(θ) so θ, the angle between the two vectors and the angle between the planes, is given by cos(θ)= u.v/(|u||v|).


In particular, the xz-plane has normal vector j. If the other plane is given by Ax+By+Cz= D, its normal vector is Ai+Bj+Ck. The dot product of those is simply B so the angle between the planes is given by cos(\theta)= \frac{B}{\sqrt{A^2+B^2+C^2}}.
 
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