Distance, Acceleration and Time Question

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A helicopter accelerates at 5.0 m/s² for 11 seconds, prompting a calculation for the total distance traveled. The initial attempt used the formula y = 1/2*a*t², resulting in 300 meters. However, the correct answer is 460 meters, indicating a miscalculation. Participants suggest checking arithmetic to resolve the discrepancy. Accurate calculations are essential for determining distance in physics problems.
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Homework Statement



If you are in a helicopter and the helicopter lifts off at a constant acceleration of 5.0m/s^2 for 11.0 seconds, what is the total distance traveled from the ground?

Homework Equations



y = yo + voyt + 1/2*ax*t^2

The Attempt at a Solution



y = 0 + 0 + 1/2(5m/s^2)(11^2)

y = 3*10^2m

But, apparently the actual answer is 4.6*10^2m.
 
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student34 said:

Homework Statement



If you are in a helicopter and the helicopter lifts off at a constant acceleration of 5.0m/s^2 for 11.0 seconds, what is the total distance traveled from the ground?

Homework Equations



y = yo + voyt + 1/2*ax*t^2

The Attempt at a Solution



y = 0 + 0 + 1/2(5m/s^2)(11^2)

y = 3*10^2m

But, apparently the actual answer is 4.6*10^2m.


Check your arithmetic.


Added in Edit:
Simon Bridge said:
Guess I have to check mine too :(
I'll check mine instead !

DOH !
 
Last edited:
Guess I have to check mine too :(
 

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