1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Distance Between 2 Objects

  1. Nov 7, 2007 #1
    A hot air balloon is rising at 5.0 m/s when a bag is released. Five seconds later, how far below the hot air balloon is the sand bag. Answer: 122.5 m.

    So I use the equation (1/2)(a)(t)^2 to figure out the distance the bag has traveled. I use the equation -Vt to figure out how far the balloon has risen. I end up getting 97.5 m when I combine the 2 but when I use just (1/2)(a)(t)^2, I get the correct answer.. Can someone please explain to me what I'm doing wrong?
     
    Last edited: Nov 7, 2007
  2. jcsd
  3. Nov 7, 2007 #2
    did you take into account that when the sandbag begins to fall it has an upward velocity of 5m/s?
     
  4. Nov 7, 2007 #3
    Wow! I can't believe I forgot about that. Thanks a lot.
     
  5. Nov 7, 2007 #4

    Chi Meson

    User Avatar
    Science Advisor
    Homework Helper

    The actual equation is [tex]d=v_o t + 1/2at^2[/tex]
     
  6. Nov 7, 2007 #5
    Thanks!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Distance Between 2 Objects
Loading...