Distance Travelled by Doubled Mass Block with Unchanged V0

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When a block is pushed with an initial velocity V0 and then stops after sliding distance D, doubling the mass while keeping V0 constant affects the stopping distance. The discussion centers on applying Newton's second law (F=ma) to relate force, mass, and acceleration. The absence of friction simplifies the problem, allowing for the derivation of a relationship between the original distance D and the new distance after mass is doubled. Participants suggest setting up equations to express the new distance in terms of D, indicating that the solution should yield a ratio like 0.5D or 0.25D. The key takeaway is that the distance the block slides before stopping is directly influenced by its mass and initial velocity.
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Homework Statement


A block pushed along the floor with velocity V0 slides a distance D after the pushing force is removed.

If the mass of the block is doubled but its initial velocity is not changed, what distance does the block slide before stopping? Express your answer in terms of D.


Homework Equations


F = ma


The Attempt at a Solution



My only problem with this question, is that I simply don't know how to relate force, velocity and distance into an equation. I've tried rearranging Newtons, but I can seem to get the right ratio. Thanks for you time.
 
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Here's my take- when you stop pushing the block it will SLOW DOWN (this is acceleration, just negative).

F=ma

So what are you constants 1?

What is your variable?

what level are you at? is friction involved in the problem, or did you type the whole thing?
 
There is no friction invloved. What i typed, is exactly, and everything the problems gives. Their not looking for a numerical answer. Something like 0.5d or 0.25d or something.
 
ok, so assume F stays the same you can set up 2 equations- what would they look like ?
 
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