Distance Velocity Graph: What Does the Area Represent?

AI Thread Summary
In a distance versus velocity graph, the area does not represent time; rather, it reflects the relationship between distance and velocity. The gradient of the graph indicates acceleration, while the area under the curve is not directly linked to time. To analyze the graph effectively, it's essential to provide context about the specific situation being modeled, including the quantities involved. Without this information, it's challenging to determine how the variables relate to each other. Understanding these concepts is crucial for interpreting the graph accurately.
Balti
Messages
6
Reaction score
1
Summary: Gradient = Acceleration(?)
Area = Time (?)

Good evening,

I have a problem that presents itself in a distance (y) velocity (x) graph. I've never come across this, and in my Physics textbook, the section dedicated to graphs does not have it.

My question is, what does the area of the graph represent? Time?
 
Physics news on Phys.org
Welcome to the PF. :smile:

Please attach the figure to a reply. Since this is a schoolwork question, I will move this thread to the schoolwork forums for you. Thanks.
 
In addition to attaching a figure, perhaps you could tell us something about the situation being modeled. What is happening? What distance is being graphed? What velocity is being graphed?

There's no way we can tell you how two random quantities are related without knowing what those quantities are.
 
  • Like
Likes berkeman
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top