Does a Black Body's Emission Rate Challenge the 2nd Law of Thermodynamics?

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1. Keeping the temperature constant, does the rate of emission from a black body depend solely on its surface area?

2. If it does, let's consider the following: we have two black bodies in our system, A and B lying close to each other. Both are at same temperature but the surface area of A is twice that of B. Now, the rate of emission from A should also be twice that of B. This implies that over a certain time, A loses more energy than it gains. So its temperature should drop. But doesn't that violate the 2nd law of Thermodynamics?

(it's not really a HW question, just a thought that popped up in my mind)
 
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QwertyXP said:
let's consider the following: we have two black bodies in our system, A and B lying close to each other. Both are at same temperature but the surface area of A is twice that of B. Now, the rate of emission from A should also be twice that of B. This implies that over a certain time, A loses more energy than it gains. So its temperature should drop. But doesn't that violate the 2nd law of Thermodynamics?

If the system in question consist just of those two bodies, and if the energy they emit is lost in space - there is no problem. They don't have to cool at the same speed.

If the system in question consist just of those two bodies, and if the energy they emit is reflected back - larger body absorbs the energy in speed proportional to its surface, that is, twice faster, so its temperature doesn't change. There is no problem.
 
Thanks for replying.

For the two possibilities that you mentioned, indeed there wouldn't be any problem.

But what if we somehow ensure that all of A's radiation falls on B (without any of it reflecting back to A), and vice versa? Then the temp of B would increase and that of A would decrease.
 
If we "somehow ensure" you are right. But 2nd law tells that it is impossible. It may sound like a circular reasoning, but it is not - it just just tells you that you have to actually design and implement system that "somehow ensures" before you can state 2nd law is violated.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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