Does adding heat affect work done by gas on its surroundings?

AI Thread Summary
Adding heat to a gas during a cycle influences the net work done by the gas on its surroundings. In this case, the work done by the gas is calculated by considering the individual work values: Wbc is -3315.4J and Wca is -2108.98J. The total work done can be determined by summing these values, resulting in a net work of -5424.38J. The net heat added to the gas is 1200J, which indicates that the gas does work on its surroundings despite the heat input. Therefore, the relationship between heat added and work done is crucial in understanding the thermodynamic cycle.
nrc_8706
Messages
69
Reaction score
0
if heat is added to a gas for the entire cycle, does that affect the net work done by the gas on its surroundings for the entire cycle?
 
Physics news on Phys.org
Wbc=0 Wab=-3315.4J Wca=nRTLn(Va/Vc)=-2108.98

The net heat added to the gas for the entire cycle is 1200J. Determine the net work done by the gas on its surroundings for the entire cycle.


Don't you just add the works?
 

Attachments

  • 01-18-2006 05;29;34PM.JPG
    01-18-2006 05;29;34PM.JPG
    37.2 KB · Views: 436

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Confusion about work done by a gas - Thermodynamics
Replies
15
Views
1K
Work done in a chamber with gas undergoing adiabatic free expansion?
Replies
13
Views
2K
Thermodynamic Work vs Mechanical Work
Replies
3
Views
922
Internal Energy of Gas and Work done
Replies
10
Views
2K
Calculating Work Done by Gas at Constant Pressure
Replies
2
Views
2K
Work done by gas expanding into a cylinder+piston system
Replies
3
Views
2K
Thermodynamic Cycle -- Work done as a function of Heat absorbed
Replies
3
Views
2K
Help Calculate Work Done in Adiabatic Process & Fill Table
Replies
19
Views
2K
Calculating work done by a gas
Replies
2
Views
761
Forces involved in principle of virtual work
Replies
2
Views
736

Hot Threads

Recent Insights

Back
Top