Does Every Subsequence of a Sequence Converge to the Same Limit?

mrroboto
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Homework Statement



Suppose that {Xn} is a sequence in R. Prove that Xn converges to a if and only if every subsequence of Xn converges to a.

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The Attempt at a Solution



Let e>0, choose N in N st n >=N implies |Xn-a| <e. Since a subsequence, nk, is in N and n1<n2<n3..., then nk>=k for all k in N. So, k>= implies |Xnk-a|<e.

That's the first part, but I can't figure out how to start the proof the other way around. i.e. how do you prove that a convergent subsequence implies a convergent sequence?
 
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It seems to me the sequence must be Cauchy for it to work.
 
Any sequence is a subsequence of itself. So it's a tautology really.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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