Does Fastener Member Stiffness Need to be Multiplied by 2 in Calculations?

  • Thread starter Thread starter djdoug99
  • Start date Start date
  • Tags Tags
    Member Stiffness
AI Thread Summary
In calculating the spring rate for fasteners, it is sometimes necessary to multiply the rate by 2 to account for the behavior of the components under load. This adjustment is often made when both ends of a member can move, allowing for radial expansion or contraction in two directions. The total spring rate is then derived by adding the adjusted rates of each component, such as in the case of a cylinder head and cylinder. This method ensures a more accurate representation of the system's stiffness. Understanding this principle is crucial for precise mechanical design calculations.
djdoug99
Messages
15
Reaction score
0
I am going through Shigley's Mechanical Design book and have a quick question on fasteners. Sometimes when calculating the spring rate for a member, you have to multiply the rate by 2, why is this? For instance in this problem
http://imgur.com/2ug9AaR

When the spring rate is calculated for both the cylinder head and cylinder, both spring rates are multiplied by 2 and then added together to get the total Km. (This is not a homework problem)

Thanks.
 
Last edited:
Engineering news on Phys.org
I'm not familiar with the precise context, but could it be because the objects can expand/contract radially in two directions (whereas if fixed at one end could only expand/contract axially in one)?
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
Back
Top