Does mean velocity equal group velocity of wave packets in QM?

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fxdung
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Does mean velocity of particle equal group velocity of wave packet in QM?If they do not equal which of them is classical velocity?
 
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fxdung said:
Sum of v*probability of given v
##m \times## the expectation value of ##k##, the Fourier transform of ##x## ?
 
As your teaching Ehrenfest theorem: mxd/dt<r>=<P>,now I can understand group velocity equal mean velocity and equal classical velocity.
 
The expectation value is given by the operator of the quantity you want to calculate the expectation value for. The velocity operator (in the Schrödinger picture) is given by
$$\hat{\vec{v}}=\frac{1}{\mathrm{i} \hbar} [\hat{\vec{x}},\hat{H}].$$
For a usual simple Hamiltonian
$$\hat{H}=\frac{1}{2m} \hat{\vec{p}}^2+V(\hat{x})$$
you get
$$\hat{\vec{v}}=\frac{1}{m} \hat{\vec{v}}.$$