Does Modular Arithmetic Prove a Prime Divides Infinite Repetitive Digit Numbers?

keityo
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if p is any prime other than 2 or 5, prove that p divides infinitely many of the integers 9, 99, 999, 9999, ... If p is any prime other than 2 or 5, prove that p divides infinitely many of the integers 1, 11, 111, 1111, ...

Is there a way to do this problem using modular arithmetic? Thanks
 
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Yes.
 
I am stuck. Could you help me?
 
Where are you stuck? What have you done so far?
 
On getting started.
 
keityo said:
On getting started.

Can you prove that at least 2 different powers of 10 have to be equal to each other mod p?
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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