Does Ohm's Law still apply when the total number of Amps is limited?

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SUMMARY

Ohm's Law, defined as I = V/R, remains applicable even when the total number of charge carriers is limited. The discussion clarifies that while high voltage can exist, the current will not drop to zero instantly; instead, it will gradually decrease as charge carriers are depleted. This relationship emphasizes that a finite number of charge carriers will ultimately affect both voltage and current, confirming that Ohm's Law holds true under these conditions.

PREREQUISITES
  • Understanding of Ohm's Law and its formula (I = V/R)
  • Basic knowledge of electrical circuits and charge carriers
  • Familiarity with concepts of voltage and current
  • Awareness of the relationship between charge carriers and electrical properties
NEXT STEPS
  • Research the implications of limited charge carriers on circuit behavior
  • Explore advanced topics in electrical engineering related to voltage and current relationships
  • Study the effects of high voltage scenarios on circuit performance
  • Investigate practical applications of Ohm's Law in real-world electrical systems
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Electrical engineers, physics students, and anyone interested in the principles of electrical circuits and the application of Ohm's Law in varying conditions.

Simfish
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As in, what if you have a VERY high voltage? Then I = V/R.

But what if you only have a limited number of charge carriers that could eventually run out? Then what will happen to the current? Will it suddenly stop following Ohm's Law? Will it immediately drop off to 0, or gradually drop off to 0?
 
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You can't have high voltage without enough charge being separated, so when you run out of charge carriers, you run out of high voltage as well.
 
Oh okay. That resolves the conundrum!
 

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