Is y' = dy/dx? Solving for dy/dx in a Test Question

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General_Sax
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I was given a question on a test today to find dy/dx.

both y and x were involved in the expression.

I solved for y'

Did I awnser the question correctly, ie, is y' = dy/dx?
 

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yes, y' is just another notation.
 
y' was Newton's notation, dy/dx was Leibniz's notation.
 

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