Domain of f(x) from -9 to 10 - Pre-calc Function

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The domain of the function f(x) = √(x² - 3x + 2) is determined by the requirement that the expression under the square root must be non-negative. To find the domain, the quadratic x² - 3x + 2 must be greater than or equal to zero, which factors to (x - 1)(x - 2). The critical points are x = 1 and x = 2, leading to intervals where the function is defined. The valid domain in interval notation is [-9, 10], as values outside this range do not satisfy the non-negativity condition. Therefore, the domain is not all real numbers but specifically the interval where the function yields real values.
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i was wondering, it says use interval notation to describe the domain of the real function, but a real function means the domain is a set of real numbers. does it mean all real numbers? i graphed it on my calculator and got [-9,10] but i have no idea if i should have negative infinity to positive infinity for all real numbers??

f(x)=square root of (x squared -3x+2). what's the domain!? :confused:
 
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