How to Calculate Buoyant Force and Volume of a Submerged Object?

AI Thread Summary
The discussion centers around calculating the buoyant force and volume of a submerged object, specifically a chunk of carbon steel. The buoyant force can be determined using the weight difference in air and water, which is 39 N. To find the volume, the relationship between density, mass, and volume is utilized, alongside the known densities of air and water. The user seeks clarification on the calculations, particularly how to derive the volume from the provided data. Ultimately, the conversation emphasizes the importance of understanding buoyancy principles in physics.
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doppler effect quick question!

Homework Statement



An ambulance traveling at speed 31 m/s is producing a loud sound of frequency 895 Hz. You see the ambulance in your rear view mirror as the ambulance approaches you and you slow down to 14 m/s as a law obeying citizen (hehehe we know now).

Homework Equations



fo=fs((v +- Vo)/(v+-Vs))

should it be:

895 (330-14)/(330-31)?

The Attempt at a Solution

 
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You are wright.
 


hi, thanks so much! i got that one... will you look at this one? I feel like I am so close.

https://www.physicsforums.com/showthread.php?p=2286412#post2286412

OR

A chunk of carbon steel with density, ρ = 7.84 g/cm3 , is completely submerged in fresh water. The chuck of steel weighs 39 N more in air than in water. Please answer the following:
(a) Find the buoyant force acting on the chuck of steel.
N
(b) Find the the volume of the chuck of steel.
m3
(c) What is the mass of the chuck of steel?

2. Homework Equations


Fw(air)=Fw(water) + 39 N

d=m/v

Fb=gp(f)V

BUT I don't know how to find the volume.

density of air is 1.16 kg/m3
density of water is 1.0x10^3


3. The Attempt at a Solution

once I get the VOLUME I can find the relative weights by using rho*g*v
and Fw(water)+ 39N = Fw(air)
 
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