Doppler effect sensitive parabolic sound collector

Click For Summary

Homework Help Overview

The problem involves a tuning fork dropped into the Grand Canyon and the application of the Doppler effect to determine its natural frequency based on the observed frequency of sound recorded by a parabolic sound collector. The context includes the speed of sound and the motion of the tuning fork as it falls.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the Doppler effect formula, questioning the correct interpretation of the variables involved, particularly the speed of the tuning fork at the time of sound emission.

Discussion Status

There is an ongoing exploration of how to account for the timing of sound emission relative to the tuning fork's motion. Some participants suggest that the speed of the fork at the moment of sound emission is crucial, while others are clarifying the relationship between the falling motion and the time it takes for sound to travel back to the observer.

Contextual Notes

Participants note the importance of understanding the timing of sound emission and the fork's velocity at that moment, as well as the total time taken for sound to reach the observer, which complicates the application of the Doppler effect formula.

Rasine
Messages
208
Reaction score
0
Using a highly sensitive parabolic sound collector, Tom records the frequency of a tuning fork as it drops into the Grand Canyon. He drops the vibrating tuning fork from rest at t=0. He records a frequency of 1887.0 Hz at t=7.880 s. What is the natural frequency of the tuning fork? Use Vsound=343.0 m/s


ok so... i want to use fr=fs(v-us)/(v)

since tom is not moving ur=0 so i did not include that in the equation and i put the negitve because the fork is moving away from tom and the waves would be longer than it it was moving towards him

us=v=vo+at so us=77.224 m/s

1887=fs(343-77.224)/343

and i get 1462.05 Hz

what did i do wrong?
 
Physics news on Phys.org
Rasine said:
He records a frequency of 1887.0 Hz at t=7.880 s.
That's the time that he records the incoming sound. When did the tuning fork emit that sound?
 
With your equation I get 2435.28Hz.
 
Rasine said:
ok so... i want to use fr=fs(v-us)/(v)
The Doppler equation for a receding sound source should be:
f_{obs} = f_{source}\frac{c}{c + v}

Where c is the speed of sound; v is the speed of the source at time of emission.
 
the sound was emitted from the fork at t=0 so how do i take that into account?
 
if the fork is falling at t=7.880 it has a v=77.224 which the equation calls for that + the speed of sound

dosent that take it into account?
 
i don't know!
 
Rasine said:
the sound was emitted from the fork at t=0 so how do i take that into account?
No, t=0 is the time that the fork was dropped. It continually vibrates as it falls, picking up speed along the way. Note that it takes time for the sound to travel from the fork back to the top of the canyon.

Rasine said:
if the fork is falling at t=7.880 it has a v=77.224 which the equation calls for that + the speed of sound
True, at t=7.88 the fork has a speed of about 77 m/s. But that's not relevant, since you want to know how fast the fork was moving when it emitted the sound that was detected (at the top of the canyon) at t=7.88.

Before you can use the Doppler formula, you need to first figure out what speed the fork had when it emitted the sound that arrived at the detector at t=7.88. Hints for figuring that out: If the fork falls for T seconds it travels a distance D. Sound emitted at that time takes D/c seconds to reach the detector. The total time must equal t=7.88 seconds.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 22 ·
Replies
22
Views
6K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K