- #1
jamiewilliams
- 11
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Homework Statement
A microphone is attached to a spring that is suspended from the ceiling. Directly below on the floor is a stationary 540-Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 2.20 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 1.83 Hz. Ignoring any reflections of sound in the room and using 343 m/s for the speed of sound, determine the amplitude (in m) of the simple harmonic motion.
Homework Equations
f(obs)= f(source) (1-(v(obs)/v))
ω=2[itex]\pi[/itex]/T
v(max)=Aω
The Attempt at a Solution
When I inquired about help I was told that I need to combine the equations for the max and min frequencies to get the maximum velocity, but I can't figure out how to do that. I am also not sure what to do with the difference of the max and min frequencies that was given in the problem. I have figured the value of ω to be 2.86 rad/s.
I think I would use the equation v(max)=Aω once I had the max velocity to get the amplitude.
I feel like this problem should be easier but I just can't figure it out!