Doppler effect train frequency question

AI Thread Summary
A passenger on a train moving at 72 km/h hears a siren at 720 Hz as it approaches a crossing signal. The passenger initially misidentified this frequency as the source frequency, leading to an incorrect calculation of the frequency after passing the signal. The correct approach involves first determining the actual source frequency, which is found to be 680 Hz. After the train passes, the detected frequency drops to 640 Hz due to the Doppler effect. This highlights the importance of distinguishing between source and detected frequencies in Doppler effect problems.
Yoruichi
Messages
17
Reaction score
0

Homework Statement



When a train running at a speed of 72 km/h approaches a crossing signal, a passenger in the train hears the siren at 720 Hz. What frequency does the passenger detect after the train passes the crossing signal? Take the speed of sound in air to be 340 m/s.

Homework Equations



Doppler effect

The Attempt at a Solution



First I convert the speed of train from 72 km/h into 20 m/s.
Speed of detector = 20 m/s
Speed of source = 0
Speed of sound = 340 m/s
Frequency of source = 720 Hz
Frequency of detector = ?

Using Doppler effect formula:

Fd = (340 - 20) / 340 x 720 (Since the detector is moving away from source, we want to make the denominator greater)
Fd = 677.64 Hz

But this isn't the answer. (The answer is 640 Hz)
May I know which part of my attempt goes wrong?
 
Physics news on Phys.org
Hello,

At first the train is approaching the crossing. So what the passenger hears is not the frequency of the siren ...
 
At first, the train is moving toward the source, so the detected frequency is shifted higher. Is 720 Hz the source frequency or the detected frequency?

When the train moves away from the source, the frequency detected by the train will be lower than the source. Use the true source frequency to compute the detected frequency in this case.
 
BvU said:
Hello,

At first the train is approaching the crossing. So what the passenger hears is not the frequency of the siren ...

Dr. Courtney said:
At first, the train is moving toward the source, so the detected frequency is shifted higher. Is 720 Hz the source frequency or the detected frequency?

When the train moves away from the source, the frequency detected by the train will be lower than the source. Use the true source frequency to compute the detected frequency in this case.

Oh I see! So the 720 Hz is actually detected frequency instead of source frequency..
Therefore I have to divide my solution into two parts, which is to find out the frequency of detector first, and then only continue with my attempt above!

720 Hz = (340 + 20) / 340 x Fs
Fs = 720 x 340/360
= 680 Hz

Fd = (340 - 20) / 340 x 680
= 640 Hz

Thanks for the clarification!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top