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odolwa99
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Having some trouble with this one. Can anyone help me out?
Many thanks.
Prove that [itex]\tan 3\theta=\frac{3\tan\theta-\tan^3\theta}{1-3\tan\theta}[/itex]
[itex]\frac{3\sin\theta}{\cos\theta}-\frac{\sin^3\theta}{\cos^3\theta}/1-\frac{3\sin^2\theta}{\cos^2\theta}[/itex]
[itex]\frac{3\sin\theta\cos\theta-\sin^3\theta}{\cos^2\theta-3\sin^2\theta}[/itex]
[itex]\frac{\sin\theta(3\cos\theta-\sin^2\theta)}{\cos^2\theta-3\sin^2\theta}[/itex]
...
Many thanks.
Homework Statement
Prove that [itex]\tan 3\theta=\frac{3\tan\theta-\tan^3\theta}{1-3\tan\theta}[/itex]
Homework Equations
The Attempt at a Solution
[itex]\frac{3\sin\theta}{\cos\theta}-\frac{\sin^3\theta}{\cos^3\theta}/1-\frac{3\sin^2\theta}{\cos^2\theta}[/itex]
[itex]\frac{3\sin\theta\cos\theta-\sin^3\theta}{\cos^2\theta-3\sin^2\theta}[/itex]
[itex]\frac{\sin\theta(3\cos\theta-\sin^2\theta)}{\cos^2\theta-3\sin^2\theta}[/itex]
...