Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Double Integral with base e

  1. Nov 20, 2009 #1
    [tex]
    \int_0^1\int_0^y e^{x^2} dx dy
    [/tex]

    The region I am integrating over should look like this graph, right?


    I tried switching the bounds but I am left where what I started.

    since 0 < x < y, and 0 < y < 1

    I can switch to 0 < x < 1 , and x < y < 1

    leaving me with the integral [tex]
    \int_0^1\int_x^1 e^{x^2} dy dx
    [/tex]

    integrating gives ex2y

    then substituting the values for y gives [tex]
    \int_0^1 e^{x^2} - e^{x^2}x dx
    [/tex]

    Am I integrating over the wrong bounds? I know if 0 < y < x, it would work.
     

    Attached Files:

  2. jcsd
  3. Nov 20, 2009 #2

    LCKurtz

    User Avatar
    Homework Helper
    Gold Member

    Everything looks correct and you reversed the limits nicely. I suspect a typo in your textbook. (Of course you can do the second integral but that doesn't help).
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Similar Discussions: Double Integral with base e
Loading...