How do I find the acceleration of a double plane system with friction?

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To find the acceleration of a double plane system with friction, the initial approach involves using the formula a = (m1g sin(alpha) - m2g sin(beta))/(m1+m2) without friction. The inclusion of friction requires adjusting the equation to account for the frictional forces acting on each block. There is uncertainty about how to incorporate the tension from one block when calculating the normal force of the other. The discussion also touches on the interpretation of the tension equation Tension - mg = -ma, questioning its clarity regarding acceleration. Seeking clarification from a professor is recommended before concluding any discrepancies in the equations.
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In this problem I'm asked to find the acceleration in the positive x direction.

How do you solve problems like this? I solved one earlier just like this except sans friction and I used (and it worked)

a = (m1g sin(alpha) - m2g sin (beta))/(m1+m2)

so for this one I tried a = ((m1g sin(alpha) - m1(mu)g cos(alpha)) - (m2g sin (beta) - m2(mu)g cos(beta))/(m1+m2)

I think the problem is that I didn't include the tension of the other block when finding a blocks normal force, but I'm not sure how to go about finding this.

Also, In our text, for a mass hanging straight down held by a string, it gives the equation Tension - mg = -ma

does this just mean that the force of tension minus the force of gravity equals the total acceleration of the mass?

Much thanks to anyone who contributes some advice or direction.

the diagram
 
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anybody? on either question?
 
No need to add tension in the normal reaction because it is tangential. Looks good.

Ind second why -ma ? If a is unknown you will get the correct sign automatically, only + acc. will be upward.
 
that's what i thought, but that's what's in the text
 
If there is no any other reference it looks odd.
Even then before considering it wrong show it to your prof.
 
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