What is the drag force on a missile at low altitude?

AI Thread Summary
To calculate the drag force on a missile with a diameter of 48 cm cruising at 270 m/s at low altitude, the drag force formula Fd = -1/2p(v^2)CA is used, where p is air density, v is velocity, and C is the drag coefficient. The user mistakenly used the diameter instead of the cross-sectional area in their calculations. The correct approach involves approximating the missile as a cylinder and calculating the cross-sectional area using the formula A = π(d/2)^2. After correcting the area, the drag force can be accurately computed. Understanding the geometry of the missile is crucial for proper calculations.
djester555
Messages
10
Reaction score
0

Homework Statement


Missile Calculate the drag force on a missile 48 cm in diameter cruising with a speed of 270 m/s at low altitude, where the density of air is 1.2 kg/m3. Assume C = 0.75.



Homework Equations



Fd = -1/2p(v^2)CA

The Attempt at a Solution



-1/2(1.2)(270^2)(0.75(0.48) = -15746.4 what am i doing wrong?
 
Physics news on Phys.org
0.48 is the diameter, not the cross-sectional area of the missile.
 
how do i calculate cross-sectional area?
 
djester555 said:
how do i calculate cross-sectional area?
Err...
Well, the usage of the term 'diameter' and general impression of the appearance of the missile should clearly hint towards approximating it as a cylinder / having a round cross-section at least.
 
The question mentions diameter, so you're supposed to assume the missile is a cylinder.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top