MHB Draw out the circuit diagram for the following 2 output circuit

AI Thread Summary
The discussion revolves around interpreting a Verilog module for a two-output circuit and clarifying syntax issues. Participants highlight confusion regarding the expression "f(~y&~x)", which appears to suggest a function call but lacks proper declaration, leading to compilation errors. Corrections are made regarding the use of lowercase for "module" and the absence of a semicolon after "endmodule." The correct interpretation reveals that "f" is a variable rather than a function, and the circuit can be drawn by following the order of operations involving AND, OR, and NOT gates. Understanding these details is essential for accurately designing and representing the circuit.
shamieh
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Draw out the circuit diagram for the following 2 output circuit specified in the following Verilog module (AND - &, Or - |, Not - ~). Use AND, OR and Inverter Gates.

Module test1(f,g,x,y,z);
input x,y,z;
output f,g;

assign g = f(~y&~x);
assign f = x&y | ~x&z;
endmodule;

Here is my solution:

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shamieh said:
Module test1(f,g,x,y,z);
input x,y,z;
output f,g;

assign g = f(~y&~x);
assign f = x&y | ~x&z;
endmodule;
I am not familiar with Verilog (I am using another software that uses file extension .v :)), but I don't understand "f(~y&~x)". Since there is no operator between f and (~y&~x), it looks like a function application, but f has not been declared a function (this requires the "function" keyword). I tried to compile this code on www.compileonline.com, and it seems to say the same thing:
Code:
main.v:5: error: No function f in this context (test1).
main.v:5: error: Unable to elaborate r-value: f((~(y))&(~(x)))

Besides, "module" in Verilog is written with a lowercase m and apparently there should not be a semicolon after "endmodule". If you want to design circuits, you have to be extra careful about such things.
 
the f in f(~y&~x) means like the function f. So it's essentially saying that the function g = f (f = x&y | ~x&z;) OR (~y&~x); see what I'm saying?

and the endmodule should have been lower case. Mistake on my part.
 
Evgeny.Makarov said:
I am not familiar with Verilog (I am using another software that uses file extension .v :)), but I don't understand "f(~y&~x)". Since there is no operator between f and (~y&~x), it looks like a function application, but f has not been declared a function (this requires the "function" keyword). I tried to compile this code on www.compileonline.com, and it seems to say the same thing:
Code:
main.v:5: error: No function f in this context (test1).
main.v:5: error: Unable to elaborate r-value: f((~(y))&(~(x)))

Besides, "module" in Verilog is written with a lowercase m and apparently there should not be a semicolon after "endmodule". If you want to design circuits, you have to be extra careful about such things.

I got mine to compile fine. It was a typo on my part originally i put a semicolon at the end which was wrong, but if you copy and paste this in the compiler you just linked me, it compiles and executes fine. But how do I actually draw this monster?:eek: Here is the code that will compile below if you want to try for yourself.
Code:
module test1(f,g,x,y,z);
    input x,y,z;
    output f,g;
    
    assign g = f|(~y&~x);
    assign f = x&y|~x&z;
endmodule
 
shamieh said:
Code:
module test1(f,g,x,y,z);
    input x,y,z;
    output f,g;
    
    assign g = f|(~y&~x);
    assign f = x&y|~x&z;
endmodule
This makes a big difference because now there is an OR after f. So f is not a function, but a regular variable. Before, even if f had been declared a function using the "function" keyword, it would have been unclear how f, which depends on two inputs x and y, can be applied to a single argument (~y&~x).

If you understand the order of evaluation, drawing a circuit is easy.

(1) x and y go to an AND
(2) x gets inverted and with z goes to an AND
(3) outputs of (1) and (2) go to an OR
(4) y and x get inverted and to to an AND
(5) outputs of (3) and (4) go to an OR.
 
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