What is the sigma bond count for 2 hydrogen in sulfuric acid?

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The discussion centers on the molecular structure of sulfuric acid (H2SO4) and the bonding configuration of its constituent atoms. It highlights the central role of sulfur (S) with a valence of 6, surrounded by four oxygen (O) atoms, where two are involved in pi bonding and two in sigma bonding. The conversation emphasizes the electron count, noting a total of 16 electrons from the bonds, but raises questions about the distribution of these electrons, particularly concerning the hydrogen (H) atoms and the overall charge of the molecule. The participants suggest that the electron count must align with the charge of sulfuric acid, indicating a need for careful consideration of bonding types and electron distribution in understanding the molecular structure.
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I tried to use VSERP to draw the shape of H2SO4
but consider
S :6 (group6)
4O :2*4
2H :1*2
-----------
16=>4pi bond
but then 4 pi bond of oxygen=16 electrons
how about the sigma bond of 2 hydrogen
 
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From memory SO4(-2) has the S as the central atom, two O's oppositely have a pi bond, and the remaining two have sigma bonds each with a negative charge. The H's are attached to these O's.
 
thunderfvck said:
From memory SO4(-2) has the S as the central atom, two O's oppositely have a pi bond, and the remaining two have sigma bonds each with a negative charge. The H's are attached to these O's.
but then it becomes
S:6
2O:1*2(sigma)
2O:2*2(pi)
2H:1*2
----------
14
but 2pi+4sigma=16
again, it does not work
 
Hint: Look at your electron count and then look at the charge on sulfuric acid.
 
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