# Drinking Fountain Lab

## Homework Statement

Calculate the initial velocity at which water exits the spout of a common drinking fountain

V1y=V1sinΘ

## The Attempt at a Solution

I measured the total distance travelled by the water in the x-direction (dx), and I got 13.2 cm. I also measured the maximum height and got 8.8cm. I used the kinematic formula (V2y^2=V1y^2+2aydy), so I had:

V2y^2=V1y^2+2aydy
0=V1y^2+2(-9.8)(8.8)
V1y= 13.3 m/s

I calculated the angle using the tan formula, so I got:
Θ=tan-1 (8.8/6.6)
Θ=53 degrees

Since I had the angle and V1y, I used these two to get V1x:

tanΘ=V1y/V1x
V1xtan53=13.3
V1x= 9.89m/s

Then I just used the pythagorean theorem to solve for V1. Would my method be correct?