Drop in pressure, what volume is left?

AI Thread Summary
The discussion revolves around calculating the volume of liquid nitrogen remaining in a vessel after a pressure drop from 100 Psi to 47 Psi due to a leak. The initial approach using the equation P1V1 = P2V2 is questioned, as it may only apply to closed systems. Participants express uncertainty about the problem's wording and the sufficiency of the provided information. The need for clarification on how to accurately solve the problem is emphasized. Overall, the thread highlights the complexities of pressure-volume relationships in open systems.
Hexxor
Messages
3
Reaction score
0

Homework Statement



There is a vessel with 10 Liters of Liquid Nitrogen.
The normal pressure is 100 Psi.
After a couple hours the pressure is dropped to 47 Psi because of leak in the vessel.

How much of the Liquid Nitrogen did we lose/is left in the vessel?

Homework Equations



I'm really not sure. I thought about P1V1 = P2V2, but I don't think that will work here.

The Attempt at a Solution



Using P1V1 = P2V2 I got an answer, but I think that will only work for a closed system (drop in pressure means increase in volume and vice versa)

So, does anyone have an idea how to solve this?
 
Physics news on Phys.org
What is the exact wording of this problem (not your paraphrasing)? There seems to be information missing.

Chet
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top