Dynamics of block with friction how to set up?

AI Thread Summary
To determine the force required to slide a 2.0 kg wood box down a vertical wall at a constant speed while pushing at a 45-degree angle, the coefficient of kinetic friction (Mk) is 0.2. The initial calculation of the applied force (Fa) was incorrect, yielding 27.71 N instead of the correct 23.1 N. The error stemmed from not accounting for all forces acting in both the y and x directions. A thorough analysis of these forces is necessary to arrive at the correct solution. Understanding the dynamics of friction and force balance is crucial for solving this problem accurately.
fizziksc
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Homework Statement


a 2.0 kg wood box slides down a vertical wood wall while you push on it at a 45 degree angle. what magnitude of foce should you apply to cause the box to slide down at a constant speed? I know that Mk = .2 (wood on wood)


Homework Equations





The Attempt at a Solution



I tried to solve it with setting the forces in the y direction. I keep getting it wrong. i said Fy=0=Fasin\vartheta - 19.6 N then solved and got Fa = 27.71 N. however the answer is Fa = 23.1 N
 
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fizziksc said:

Homework Statement


a 2.0 kg wood box slides down a vertical wood wall while you push on it at a 45 degree angle. what magnitude of foce should you apply to cause the box to slide down at a constant speed? I know that Mk = .2 (wood on wood)


Homework Equations





The Attempt at a Solution



I tried to solve it with setting the forces in the y direction. I keep getting it wrong. i said Fy=0=Fasin\vartheta - 19.6 N then solved and got Fa = 27.71 N. however the answer is Fa = 23.1 N
You have to look at all forces in the y direction. You missed one. You're going to have to look for all forces in the x direction as well.
 
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