Dynamics Question: Solving for Force in a Frictionless Ramp Scenario

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A frictionless ramp scenario involving a 5kg block on a flat-bed truck is analyzed to find the force exerted by the truck's engine. The block remains stationary relative to the ramp while the truck accelerates. Initial calculations for acceleration were incorrect, with a revised value of 5.26 m/s² determined later. The net force was calculated as 24.09 N, leading to a final engine force of 68,640 N for the 12,000 kg truck. The importance of free body diagrams and Newton's second law in solving such dynamics problems is emphasized.
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Dynamics Question

Homework Statement



1. Homework Statement
A flat-bed truck with a frictionless ramp accelerates forward.


(That 35 is the angle, and a 5kg block rests on the hypotenuse)


/ |
--- / l
- - /35deg l
- ---------------
-----------------
-o-----------0--

The acceleration of the truck is suck that a 5.0kg block is stationary (relative to the ramp). If the rolling coefficient of friction is (mew=0.10) Find the force the engine is exerting on the 12000kg truck.


Homework Equations


F=ma Ff=mewFn Fg=mg


The Attempt at a Solution


Well...frankly, I really don't know how to start this question. How do I know where to start first? I'm wondering if I need acceleration in this or not, but I got a=0.98 m/s2 assuming that the truck's accel and the box's are the same.

Ok, so I reattempted it finding Fparallel as 40.138N assuming Fparallel is = to Fn
I found Ff as 4.0138N, and looked for Fperpendicular which = to 28.105N
I subracted Ff from Fperpendicular to find Fnet which I got as 24.09.
I took the Fnet and divided by the mass of the crate which is 5kg on the ramp which got me 4.82m/s2

Assuming that the acceleration of the box, and the acceleration of the truck to be the same,
I did Fnet=ma which is Fnet=12000 x 4.82 = 56840N

It's a pretty big number, and I'm wondering if anyone can help me confirm if I did it right.
 
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Faylight said:

The Attempt at a Solution


Well...frankly, I really don't know how to start this question. How do I know where to start first?

You always start this sort of problem by drawing free body diagrams and applying Newton's second law to them. Look at the examples in your book and notes. You should see this.

I'm wondering if I need acceleration in this or not, but I got a=0.98 m/s2 assuming that the truck's accel and the box's are the same.

It's true that the truck and the box have the same acceleration, but that common acceleration is not 0.98 m/s2. How did you get this?
 
For the acceleration, I got that wrong so I redid it, and I ended up with a new acceleration of 5.26m/s2
 
hi, i was wondering if you figured out the final answer to this question?
 
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