Earnshaw's Theorem and electrostatics

AI Thread Summary
Earnshaw's Theorem states that stable equilibrium cannot exist in electrostatics, as demonstrated through the contradiction arising from applying Gauss' Law at a point of assumed stable equilibrium. When analyzing a charge Q at point P, the necessary electric field direction contradicts the conditions for stable equilibrium. The discussion also explores the stability of a test charge q placed at the center of a square formed by four point charges Q at the corners, noting that certain movements lead to unstable equilibrium. The confusion arises from the divergence being zero, which suggests a metastable state rather than true stability. Overall, the key takeaway is that while certain configurations may appear stable, they do not satisfy the criteria for stable equilibrium as defined by Earnshaw's Theorem.
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Homework Statement


14: a: It is impossible to have a stable equilibrium in electrostatics. This idea is known as Earnshaw’s Theorem. Let’s prove this fact. Assume that at a particular point P that a charge Q is in a stable equilibrium. Think about the direction of E⃗ necessary for the equilibrium. Now use Gauss’ Law with a spherical gaussian surface centered on P. Show that this leads to a contradiction.
b: Imagine a square in the xy plane with a point charge Q fixed at each corner. Now put a test charge q in the exact center of the square. What direction(s) can we move q in for which the equilibrium is stable? For which it is not stable? Explain.


Homework Equations


Gauss's equation: (E*A)/(Qenclosed*(Permittivity of free space))


The Attempt at a Solution


I've figured out that the direction of E has to be inward, but i don't understand why. With some research I've found the proof where the divergence comes out to zero, but wouldn't that mean it achieves stable equilibrium? Seems a bit contradictory. Also, if you use a spherical versus a circular surface, you get a difference in answer by a factor of 1/3... That's the best i can do. Please help.
 
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arishorts said:
the divergence comes out to zero, but wouldn't that mean it achieves stable equilibrium?
No, that could be metastable, like a ball on a surface that is fully horizontal.
 
I like your analogy, a lot actually. But how can i prove that using Gauss' theorem leads to a contradiction?
 
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