Earth's Gravity if the Earth rotated the opposite direction

AI Thread Summary
If the Earth rotated in the opposite direction, the primary effect on weight at the equator and North Pole would stem from changes in the centrifugal force due to the altered angular velocity. The gravitational force equation remains unchanged, as the mass of the Earth and its size stay constant. The only variable affected would be the angular velocity, which would simply change sign but not magnitude, as it is squared in the equation. Therefore, weight would not significantly change because the gravitational force remains constant. Overall, the direction of rotation does not impact the fundamental calculations of weight in this scenario.
rogersjc
Messages
3
Reaction score
0
1. Suppose the Earth rotated in the opposite Direction. How would this effect your weight at the equator. At the North Pole



2. Newtons Gravity Equation and the centrifugal Force

Fg = -G*(Me*rhat/r^2) + omega^2*R + Fn

3. Since the only thing I can see that will change is the omega value it will be the opposite sign. I do not believe the gravity will change and thus the weight will not change since the omega is squared. Is that the correct way to go about solving this problem?
 
Physics news on Phys.org
The direction should have nothing to do with the result.

The mass of the Earth, its size and rate of spin are all the same.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top