mmmboh
- 401
- 0
[PLAIN]http://img811.imageshack.us/img811/3199/trainv.jpg
I have to find how long it takes the ball to travel the distance of the train in the ground frame.
In the train's frame, it is L0/u0.
Is the answer in the ground's frame simply (L0/u0)/(1-v2/c2)^(1/2)?
I have to find how long it takes the ball to travel the distance of the train in the ground frame.
In the train's frame, it is L0/u0.
Is the answer in the ground's frame simply (L0/u0)/(1-v2/c2)^(1/2)?
Last edited by a moderator: