Elastic scattering of WIMPs off nuclei

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The discussion revolves around the design of a cryogenic calorimeter for detecting Weakly Interacting Massive Particles (WIMPs), specifically neutralinos. It highlights the formula for kinetic energy transfer during elastic collisions between a neutralino and a nucleus, emphasizing that maximum energy transfer occurs when the nucleus mass equals the neutralino mass. The initial confusion regarding the differentiation process and energy plotting is clarified, confirming that the maximum is related to the adjustable nucleus mass rather than the fixed WIMP mass. The conversation concludes with acknowledgment of the misunderstanding and appreciation for the clarification. Understanding this principle is crucial for optimizing WIMP detection strategies.
maximus123
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Hello,

My problem is as follows

Suppose we want to design a cryogenic calorimeter for detecting WIMPs, such as neutralinos
(\chi). One can show that if a \chi has an elastic collision with a nucleus of mass m_N in the calorimeter, the kinetic energy transferred to the nucleus is

\Delta E=\frac{m_Nm_{\chi}^2}{(m_N+m_{\chi})^2}v^2(1-\textrm{cos}\theta)
where v is the neutralino’s velocity in the lab frame and θ is the scattering angle in the c.m.
frame.

Show that to get the maximum energy transfer for a given m_{\chi}, the nucleus should be
chosen such that m_N = m_{\chi}.
I've tried differentiating to find the maximum and I've tried plotting E against m_{\chi} for a range of values and this did not suggest a maximum at m_N = m_{\chi}. Could someone explain why it is the case that the energy transfer is maximum when these masses are equal?

Thanks a lot.
 
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It is a maximum with respect to the nuclei mass (the thing we can change), not with respect to the WIMP mass (which we cannot influence).
 
Yeah I figured that out, I was being an idiot. Thanks for the help though.
 
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