Elastic string. Ball. Kinetic energy. Confusion.

AI Thread Summary
The discussion focuses on calculating the kinetic energy (KE) of a ball attached to an elastic string when it is 0.5m above a fixed point. The elastic string has a modulus of elasticity of 12 and a natural length of 0.5m. The ball, with a mass of 0.5kg, is initially pulled down to 1.5m below the fixed point. Participants clarify that at 0.5m above the fixed point, the string is not extended, resulting in no elastic potential energy (EPE). The kinetic energy at this position is influenced by gravitational potential energy and the initial elastic potential energy when the ball was at its lowest point.
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Homework Statement


An elastic string with modulus of elasticity=12. Natural length= 0.5m. Mass of ball attached to the end of the string=0.5kg. The other end of the string is fixed at point P. The particle is pulled down until it is 1.5m below P.

Find the kinetic energy of the particle when it is 0.5m above P.



The Attempt at a Solution


The previous question asked me to prove the KE when the string was slack and I got 7.1J, I'm not sure if that is of any relevance when working out this question.

I'm confused as to what the extention is when working out the EPE or if there even is one. Any help will be greatly appreciated!
 
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At 0.5m above P there is no elastic PE.
 
Thank you for replying!

How come there is no EPE? Isn't some needed to get it back to its original shape?
 
I am assuming that EPE means elastic potential energy. But EPE is directly proportional to the extension in the string. But since the natural length of the string is 0.5m, then at 0.5m above P the string is not extended and hence has no EPE. Of course the mass has KE and grav PE both of which are the result of the original EPE when at the lowest point.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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