How Do You Calculate the Capacitance of a Charged Capacitor?

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In summary, the conversation discusses finding the capacitance of a device given that it is charged with 6.10KV and stores 1140 J of energy. The formula W = 1/2 Q Delta V is used and rearranged to find Q = -W/Delta V and then C = Q/V. The conversation also mentions a formula for finding energy from voltage and capacitance.
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Homework Statement



A capacitor is in this device is charged 6.10KV and stores 1140 J of energy. What's the capacitance?

Homework Equations


W= 1/2 Q Delta V

The Attempt at a Solution


PE is W
W= 1140 J
Delta V: 6.10 KV
Q =?
C=?

Delta V = -W/Q rewrite to Q= -W/Delta V
convert kV to V
Q= -1140/6100V= -.18

then C= Q/V -.18/6100= -3.06E -5
 
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  • #2
Inasmuch as you're given energy (Joules) would you happen to know a formula for finding capacitance from voltage and energy? (hint: The formula is usually written for finding energy from voltage and capacitance.)
 
  • #3
if C= Q/V is what your saying, C and Q isn't given in this case there only V.
 

1. What is an electric capacitator?

An electric capacitator is an electronic component that stores electrical energy in the form of an electric field. It consists of two conductive plates separated by an insulating material called a dielectric.

2. How does an electric capacitator work?

When a voltage is applied to an electric capacitator, one plate becomes positively charged and the other becomes negatively charged, creating an electric field between them. This field stores the electrical energy until it is discharged.

3. What are the applications of electric capacitators?

Electric capacitators are used in a wide range of electronic devices, such as computers, smartphones, and TVs, to store energy and regulate voltage levels. They are also used in power grids, electronic circuits, and energy storage systems.

4. What factors affect the capacitance of an electric capacitator?

The capacitance of an electric capacitator is affected by the surface area of the plates, the distance between them, and the type of dielectric material used. The capacitance is directly proportional to the surface area and inversely proportional to the distance between the plates.

5. How do I choose the right capacitator for my project?

The capacitance, voltage rating, and size of an electric capacitator are important factors to consider when choosing the right one for your project. It is also important to select a capacitator with a suitable dielectric material for your intended application.

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