(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A capacitor is in this device is charged 6.10KV and stores 1140 J of energy. What's the capacitance?

2. Relevant equations

W= 1/2 Q Delta V

3. The attempt at a solution

PE is W

W= 1140 J

Delta V: 6.10 KV

Q =?

C=?

Delta V = -W/Q rewrite to Q= -W/Delta V

convert kV to V

Q= -1140/6100V= -.18

then C= Q/V -.18/6100= -3.06E -5

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# Homework Help: Electric Capacitators 1

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