Electric Circuit Homework: Series vs. Parallel Light Bulbs

AI Thread Summary
When connecting two light bulbs rated at 60 W and 75 W in series to a 220 V source, understanding the relationship between power, voltage, and current is crucial. Power is defined as the rate of energy change, and dividing power by voltage yields current, not charge. To solve the problem, one should first calculate the resistance of each bulb using their power ratings and the voltage. The behavior of bulbs in series differs from those in parallel, affecting the total resistance and current flow. Recognizing these principles is essential for accurately determining the power dissipated by each bulb in the series configuration.
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Homework Statement


Two light bulbs are rated as 60 W and 75 W at 220 V. If these are connected in series to a source of 220 V, what will the power in each be? Assume a constant resistance for the light bulbs.


Homework Equations


W=VQ P=IV V=IR


The Attempt at a Solution


I was solving a similar question, which was dealing with bulbs connected in parallel. By dividing the work (W) by the Volt (V) I got the current (A), which seems a little strange to me since I thought I'd get the charge. Could anyone explain this please? (I then used V=IR and then P=IV to figure out the power dissipated) When it comes to light bulbs connected in series I don't know how to approach the problem or what differs between the bulbs that are connected in series and those that are connected in parallel.
 
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Hello poskhare,

Welcome to physics Forums!
poskhare said:
I was solving a similar question, which was dealing with bulbs connected in parallel. By dividing the work (W) by the Volt (V) I got the current (A), which seems a little strange to me since I thought I'd get the charge. Could anyone explain this please?
But there isn't any 'work' value given in the problem. There are power values however: the 60 [W] and 75 [W].

Power is the time derivative of work. In other words, power is the change in energy per unit time.

So when you divide the power by the emf (a.k.a. voltage), you get the change in charge per unit time. Charge per unit time is current.

In summary, the important variables to this problem involve some or all of the following:

o Power, P (and two different values were given, one for each bulb). Power has units of Watts [W].
o EMF (sometimes called 'voltage'), V. Voltage has units of Volts [V].
o Current, I. Current has units of Amperes (sometimes abbreviated as 'Amps') [A].
o Resistance R. Resistance has units of Ohms [Ω].
(I then used V=IR and then P=IV to figure out the power dissipated) When it comes to light bulbs connected in series I don't know how to approach the problem or what differs between the bulbs that are connected in series and those that are connected in parallel.
My first recommendation is to find the resistance of each bulb, based on each bulbs rated power and rated voltage.

Then study the difference between putting resistors in parallel and putting them in series. It makes a difference. :wink:
 
Okay, now I get it. Thanks a lot!
 
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