Electric Circuits Homework: Solving for Energy Delivered to Battery

AI Thread Summary
To calculate the energy delivered to a battery by a charger providing 6.0A for 5.0 hours at 12V, the relevant equations are Power = Voltage x Current and Energy = Power x Time. The total time in seconds is 18,000 seconds (5 hours). Thus, the power is 72 watts (12V x 6A), leading to an energy calculation of 1.296 x 10^6 Joules. The correct answer is approximately 1.3 x 10^6 Joules, confirming the initial claim. Understanding the conversion of hours to seconds is crucial for accurate energy calculations.
kamal242
Messages
2
Reaction score
0

Homework Statement


A battery charger is connected to a dead battery and delivers a current of 6.0A for 5.0 hours,keeping the voltage across the battery terminals at 12V in the process.how much energy is delivered to the battery?


Homework Equations


R=I^2RT



The Attempt at a Solution


the answer is 1.3x10^6 Joules but I am not getting that.can someone help me please?
 
Physics news on Phys.org
Do you know any other expressions for electrical power and energy?
 
kamal242 said:

Homework Equations


R=I^2RT


Power = Voltage x Current
Energy = Power x Time.

Joules of energy is expressed in amp-volt-seconds.

How many seconds in an hour?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »
Thread 'Minimum mass of a block'

Thread 'Minimum mass of a block'

Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
View full post »

Similar threads

Why do the headlights on the car become dim when the car is starting?
Replies
4
Views
2K
Potential difference between 2 points in a capacitor circuit
Replies
30
Views
3K
How does a simple circuit work?
Replies
12
Views
1K
Mechanisms Involved When Charging a Battery
Replies
10
Views
1K
Connecting a number of EMF sources in a circle to form a circuit
Replies
9
Views
1K
Comparing energy lost by the battery & energy gained by the capacitor.
Replies
5
Views
2K
Law of Conservation of Energy Proof
Replies
22
Views
2K
Find spring constant k using an electrical circuit
Replies
10
Views
2K
A circuit involving two non-linear resistances (incandescent lamps)
Replies
14
Views
2K
Electric Potential across charging battery.
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top