Electric circuits voltage flow question

[TheRedDevil18]

Homework Statement

Homework Equations

The Attempt at a Solution

12.1.1) I don't understand why V2 would have a reading of 12V when V=IR and there is no current flowing in the circuit, can someone please explain?

12.1.2) I think I understand why the voltage is 0 and that is because the resistance in the wires are negligible and voltage is dependant on resistance, Correct?

 

[Abstr7ct]

1) Since there's no current flowing when the switch is open, all resistors can be disregarded. When you redraw the circuit with no resistors, V₂'s leads will be connected to the anode and cathode of the battery. Therefore, V₂ should display a reading of 12V same as V₁.

2) Yes, when the switch is closed (short circuit), the reading on V₂ should be zero since the wire's resistance is negligible, or in other words, zero. Applying V=IR will result in V= 0.

 

[TheRedDevil18]

1) Since there's no current flowing when the switch is open, all resistors can be disregarded. When you redraw the circuit with no resistors, V₂'s leads will be connected to the anode and cathode of the battery. Therefore, V₂ should display a reading of 12V same as V₁.

2) Yes, when the switch is closed (short circuit), the reading on V₂ should be zero since the wire's resistance is negligible, or in other words, zero. Applying V=IR will result in V= 0.

Ok, that makes sense, Thanks for the explanation