Electric Dipole Potential Difference Calculation for a Polarized Carbon Atom

airbauer33
Messages
7
Reaction score
0
[SOLVED] Electric Dipole

Homework Statement


I have an carbon atom polarized so it is essentially a physical dipole. I know the spacing between the "two charges" and I know what the charges are. I need to determine the potential difference across the polarized atom.


Homework Equations



Not sure

The Attempt at a Solution



I think that I need to determine the potential at both ends of the physical dipole and then find the difference between them. However, there are charges at the ends, so if I try to find the potential at the ends, it is infinity. I must be thinking about this wrong.
 
Physics news on Phys.org
I think they just want the pot at one charge due to the other.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top