- #1
RonakPat
- 6
- 0
Homework Statement
What is the electric field at Point P shown below?
http://img685.imageshack.us/img685/2268/58580322.png
Homework Equations
[tex]
\begin{flalign*}
E & = & & k \ \frac{q}{r^2} \ \mbox{ or } \ \frac{1}{4 \pi \epsilon_0} \ \frac{q}{r^2}\\
V & = & & k \ \frac{q}{r} \ \mbox{ or } \ \frac{1}{4 \pi \epsilon_0} \ \frac{q}{r}\\
\end{flalign*}
[/tex]
The Attempt at a Solution
I figured that to find the electric field acting on point P, I would have to add the two separate fields from the charges.
Using the equation above, i got these answers
for the 5.6 uC I got 5,040,000 N/C
and for the -3.6 uC I got -9,000,000 N/C
and then I added them to get -3,960,000 N/C.
Maybe my thinking was wrong but, the answers my teacher gave me say that the answer to this problem is 7.20 x 106 and the angle is 56degrees N of E.
I also have no idea how to find the angle. My only thought is taking the inverse tangent?
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