Electric field and acceleration

AI Thread Summary
The discussion revolves around calculating the acceleration of a charged ice particle in an electric field during a thunderstorm. The initial calculation of force using F = qE yielded a value of 1.16e-6 N, leading to an acceleration of 1.06e-2 m/s². However, the correct answer provided by the key is 0.802 m/s², prompting the user to reconsider the forces acting on the particle. It was identified that gravitational force must also be considered, indicating that the net force should include both the electric force and the gravitational force. The final advice emphasizes the importance of accounting for all forces and their directions in the calculations.
ENCgirl
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Homework Statement



During a thunderstorm the electric field at a certain point in the Earth's atmosphere is 1.07e5 N/C, directed upward. Find the acceleration of a small piece of ice of mass 1.09e-4 g, carrying a charge of 1.08e-11 C.




Homework Equations



F= (q')(E)

a= F/mass



The Attempt at a Solution



F= (1.08 e -11 C) ( 1.07 e 5 N/C) = 1.16 e-6 N

a= F/m= (1.16 e -6)/ (1.09 e -7 kg)= 1.06 e-2 m/s^2

The above answer is what I get but the key is saying:

0.802 m/s^2


Please help me figure out what I am doing wrong.
Thank you.

Thanks again to anyone who replies. It is late here so I am signing off.. I will reply tomorrow if anyone has responded.
 
Last edited:
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Have you accounted for all the forces?
 
gneill said:
Have you accounted for all the forces?
I am not sure. I thought so because I followed the example in the book.
 
What other force do you think would be operating on a particle of mass 1.09e-4 grams?
 
gneill said:
What other force do you think would be operating on a particle of mass 1.09e-4 grams?

hmmm. Gravity? :) Wow! I think the lightbulb just came one.. :)
 
gneill said:
What other force do you think would be operating on a particle of mass 1.09e-4 grams?

So, would I take the force that is listed in the problem and add the force of gravity on the object that I solve for then take the cumulative of the two ans use that as the F in the a= F/m formula?
 
ENCgirl said:
So, would I take the force that is listed in the problem and add the force of gravity on the object that I solve for then take the cumulative of the two ans use that as the F in the a= F/m formula?

That's the general idea. Pay attention to the directions of the forces.
 
gneill said:
That's the general idea. Pay attention to the directions of the forces.

Thanks!
 
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