Electric Field and Electric Potential

AI Thread Summary
To find the electric field strength midway between two point charges, q1=5.78nC and q2=-5.78nC, separated by 68cm, the correct approach involves using the formula E=Kq/r^2. A user expressed confusion over obtaining an excessively large answer, prompting others to request clarification on their calculations and to ensure proper unit conversion from centimeters to meters. It was emphasized that the direction of the electric field must also be considered, and that specific numerical values and steps should be shared for accurate troubleshooting. Overall, clear communication of the work done is essential for resolving the issue effectively.
stonecoldgen
Messages
108
Reaction score
0

Homework Statement


Find the strength of the electric field midway between two point charges, q1=5.78nC and q2=-5.78nC separated by 68cm.


Homework Equations


Kq1q2/r2=F

\epsilon=F/q


The Attempt at a Solution


I just tried the problem as a two step equation but it's giving me a huge answer. What am I doing wrong? Thanks.
 
Physics news on Phys.org
stonecoldgen said:

Homework Statement


Find the strength of the electric field midway between two point charges, q1=5.78nC and q2=-5.78nC separated by 68cm.


Homework Equations


Kq1q2/r2=F

\epsilon=F/q


The Attempt at a Solution


I just tried the problem as a two step equation but it's giving me a huge answer. What am I doing wrong? Thanks.

Now how could anyone tell you what you are doing wrong if you don't show your work?
 
I plugged the numbers on the first equation, which gave me the force.

Then plugged force into the second equation and divided by q, but it's giving me a huge huge number.
 
Did you convert the 68cm to m?
 
stonecoldgen said:
I plugged the numbers on the first equation, which gave me the force.

Then plugged force into the second equation and divided by q, but it's giving me a huge huge number.

The magnitude of the electric field due to a charge q is E=Kq/r^2. Remember it also has a direction you need to find. I don't know how you could find a force. What value are you using for the charge at the midpoint? And I'll say this once more, "huge huge number" doesn't mean anything informative. Show your numbers. What you put in, what formulas you put it into and what you got.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top