A 12 V battery gets connected between the center conductor (black dot) and the sheath of the coaxial cable so that the voltage of the center conductor with respect to the sheath (outer contour) is +12 V. What is the approximate force on a +25C particle located at D.
The Attempt at a Solution
Electric field lines extend from the center conductor to the sheath, with field vectors pointing from the center to the outer contour.
Would the average force then just be [tex]F=(+12V*+12C)/x[/tex]
and x would merely be measured from the center conductor to the position D?
We're told the radius of the circle is 1cm.