Electric Field and potential of spherical shell

AI Thread Summary
The discussion focuses on calculating the electric field and potential of a spherical shell conductor with a central charge. The internal electric field (E_int) is derived using the formula E_int = 1/4πε_0 * Q/Ri^2, while the external electric field (E_ext) is calculated as E_ext = 1/4πε_0 * Q1/Re^2. Participants emphasize the need to consider the total charge within a general sphere of radius r2, not just the charge on the shell. There is a correction regarding the electric field formula, highlighting the importance of using 1/r^2 instead of 1/r. The conversation underscores the necessity for precision in calculating E(r) and V(r) for accurate results.
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A charge punctiform of Q= 12*10\exp-6 C is in the center of a spherical shell conductor charged negatively Q1= 6*10\exp-6 C, and of internal radius = 22 cm ad external=26 cm.
Calculate the electric field and potential.
 
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What are your thoughts/ideas on this problem? You need to show some work before you get help.
 
My reasoning is:

Ri=Internal radius
Re=External radius
E int= 1/4\pi\epsilon_0 * Q/Ri^2
E ext= 1/4\pi\epsilon_0 * Q1/Re^2

and then use

V=\int E dl

What do you think?

edit
I correct something
 
Last edited:
First off, it should be 1/r2 not 1/r. Shoudn't E_int be for a general point 0<r1<Ri, and E_ext for Re<r2<infinity, or are you calculating the field strength at those points? I don't see why else they'd give you the size of the charge and of the radii. Also, you need to consider the total charge inside your general sphere of radius r2, not just the charge on the metal sphere.
 
Tomsk said:
are you calculating the field strength at those points? I don't see why else they'd give you the size of the charge and of the radii. Also, you need to consider the total charge inside your general sphere of radius r2, not just the charge on the metal sphere.
For the precision the problem demands E(r) and V(r).
Perhaps I have not understood well what I must calculate.
 
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