Electric field at centre of a hollow hemisphere shell.

uOEE
Messages
3
Reaction score
0

Homework Statement


aPU0AKi.png


Homework Equations


CQssp2k.png

N5fF11a.png
'

The Attempt at a Solution



Please excuse the poor writing. I believe it should be legible enough, but if you have any questions, i'll clarify or rewrite it.

RdtZpbc.png


Please excuse the poor writing. I believe it should be legible enough, but if you have any questions, i'll clarify or rewrite it.

My steps for solving this was filling in the values into the formula given. Using a square differential element on the surface of the sphere, as well as spherical co-ordinates.

i'm sure i just have a small error somewhere in the math, but I'm not too sure where... I've redone the question 3 times.

These two sources, among others, show that my answer is wrong. Though I did my question differently, so i can't be sure where i went wrong.



http://www.personal.utulsa.edu/~alexei-grigoriev/index_files/Homework2_solutions.pdf
 
Physics news on Phys.org
Welcome to PF!

Looks like you treated the unit vector ##\hat{r}## as a constant vector when you pulled it out of the double integral. Does the direction of ##\hat{r}## vary as you integrate over the surface? If so, you cannot treat it as a constant vector.
 
How would I treat the vector? My apologies. Calculus is not my strong suit.
 
How would I go about doing that? Calculus is not my stop suit. And also, thanks for the help.
TSny said:
Welcome to PF!

Looks like you treated the unit vector ##\hat{r}## as a constant vector when you pulled it out of the double integral. Does the direction of ##\hat{r}## vary as you integrate over the surface? If so, you cannot treat it as a constant vector.
 
Use symmetry to see which direction the net E field will point. Then just work with the component of E that is in that direction. (Project your integrand into that direction.)
 
 
 
Back
Top