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Electric field calulation

  1. Jan 25, 2006 #1
    I'm having trouble with the question included in the attachment, part B specifically. If anyone could start me off it would be a great help!

    Also, my answer for part A is included if anyone would care to check it o:)
    -Note: Chances are it's wrong :rofl:​

    Attached Files:

  2. jcsd
  3. Jan 26, 2006 #2

    Meir Achuz

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    I can't open your attachment. Why don't you cut and paste and put it in without the attachment?
  4. Jan 26, 2006 #3
    I can't copy and paste cause it's a picture, however perhaps the following will work for you:


    Thanks a bunch!!
  5. Jan 26, 2006 #4

    Meir Achuz

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    I also get your answer to (A), with \lambda=Q/h.
    I think the easiest way to do (B) is:
    1. Use the field of a ring to get the field a distance z from a disk of charge Q. Use dq=2pi r dr/(pi r^2 Q) and integrate r from 0 to R.
    This should give E=(2Q/R^2)[1-z/sqrt{z^2+R^2}].
    2. Integrate E for the disk the same way you must have done for E for the ring for the hollow cylinder.
    Let me know if you want to know the answer.
  6. Jan 28, 2006 #5
    Cool, I got it now.

    Thanks man, and sorry for the slow reply.
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